Question

x+1÷x^3+3x^2+3x+1 find step by step

Answer 1

What are the solutions of x3−3x2−3x+1=0?

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x3–3x2–3x+1=0

⟹x3+x2–4x2–3x+1=0

⟹x2(x+1)−(4x2+3x−1)=0

⟹x2(x+1)−(4x2+4x−x−1)=0

⟹x2(x+1)−[4x(x+1)−1(x+1)]=0

⟹(x+1)(x2–4x+1)=0

Either

x+1=0⟹x=−1

Or,

x2–4x+1=0

⟹x2–4x+4–3=0

⟹(x−2)2=3

⟹x=2±3–√

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if 3x) ^1/3*(3x) ^_4/3, what is the value of x?

Why are the solutions to the equation 3x^2=6x x=2 and x=0?

X^3 – 3X – 3X^2 + 1 = 0

X^3 + 1– 3X – 3X^2 = 0

(X^3 + 1) – (3X + 3X^2) = 0

(X+1)(X^2 – X + 1) – 3X(1+X) = 0

(X+1)( X^2 – 4X + 1) = 0

(X+1)( X^2 – 4X + 4-3) = 0

(X+1)[( X– 2)^2 - 3)] = 0

(X+1)[( X – 2) + √3)( ( X – 2) - √3)] = 0

Hence X = -1 or (2 - √3) or (2 + √3).