Math, asked by sandrayee, 9 months ago

x-1/x=3
evaluate
i) x² + I/x²
i) x2 - 1/x²​

Answers

Answered by advocatedmdesai
0

Answer:

Step-by-step explanation:

x-1=3x

2x=-1

x=-1/2

i) x²+1/x²

=(-1/2)²+1/(-1/2)²

=1/4+1÷1/4

=5/4÷4

=5×4/4

=5

ii)x²=1/4

x²-1/x²=1/4-1÷1/4

=-3/4÷1/4

=-3

Answered by pug1127
0
Given that x-1/x=3
X^2+1/x^2 can be written as ((x-1/x)^2)+2
(By (a-b)^2=a^2+b^2-2ab. Here a equals x and b equals 1/x.)
Substitute the value in and you would get 11

For the second one, try finding x+1/x by the formula sqrt(x^2+1/x^2+2) try and multiply it with x-1/x we get sqrt(117)
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