x=¹/x=3,Evalute x³-¹/x³
Answers
Answer:
As we see that the x has a power of 3 so we begin by cubbing the whole equation.
So we start solving like:
[math]x + \dfrac{1}{x} = 3[/math]
[math](x + \dfrac{1}{x})^3 = 3^3[/math]
[math]x^3 + 3.x^2.\dfrac{1}{x} + 3.x.\dfrac{1}{x^2} + \dfrac{1}{x^3} = 27[/math]
[math](x^3 + \dfrac{1}{x^3}) + 3.x^2.\dfrac{1}{x} + 3.x.\dfrac{1}{x^2} = 27[/math]
[math]x^3 + \dfrac{1}{x^3} + (3x + \dfrac{3}{x}) = 27[/math]
[math]x^3 + \dfrac{1}{x^3} + 3(x + \dfrac{1}{x}) = 27[/math]
[math]x^3 + \dfrac{1}{x^3} + 3 × 3 = 27[/math]
[math]x^3 + \dfrac{1}{x^3} + 9 = 27[/math]
[math]x^3 + \dfrac{1}{x^3} = 18[/math]
Therefore the answer is 18
Answer:
If x+1/x=3, then what is the value of x³+1/x³=?
Answer
21
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26 Answers
Dave Palamar, lives in Tampa, FL
Updated April 6, 2018
Due to Parenthetical Shifts in the proper Metric Form it will not resolve as notated moreso due to facts it associates to x+(1/x)=2.5 resolve for x=.5=2
Scientific Processes toward Deduction
From the getgo we observe two Resolves reliant on If you are Plainly Forgetting Brackets, we thus derive the following as Fig. 1 to 3:
(x+1)=3x resolves with easiness as: 2x=1=2×.5x2+1=3x" role="presentation" style="margin: 0px; padding: 0px; display: inline-table; font-style: normal; font-weight: normal; line-height: normal; font-size: 15px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; position: relative;">x2+1=3xx2+1=3x however, we observe this does not atall result same easiness of resolve as 1, and we get to Figure 3 as: (Example1×(x OR 1)) To share that Same Resolve as Figure 1 must also equal 3x(y OR 1) with something more alike 2xy+x=xy+2x=3xy=x2+1" role="presentation" style="margin: 0px; padding: 0px; display: inline-table; font-style: normal; font-weight: normal; line-height: normal; font-size: 15px; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; position: relative;">2xy+x=xy+2x=3xy=x2+12xy+x=xy+2x=3xy=x2+1 via y=1 onsets that a Factor is thereat via (y or 1)=y=1 has Equality of the Two Options. And we know .5 cannot equal 1, so we know x is not equal 1 nor .5 within status of Parenthetical Shift (See 8 below)