Question

(X - 1/x)^3 expand using binomial theorem

Answer 1

Answer:

x³ - 1/x³ - 3x + 3/x

Step-by-step explanation:

=> (x - 1/x)³

$\small{=> ^3 C_0.x^3.(\frac{-1}{x})^0 + ^3C_1.x^2.(-\frac{1}{x})^1 + ^3C_2.x^1.(-\frac{1}{x})^2 + ^3C_3.x^0.(\frac{-1}{x})^3}$

=> (1)a³(1) + 3x²(-1/x)¹+ 3x¹(-1/x)² + (1)(1)(-1/x)³

=> x³ - 3x²(1/x) + 3x(1/x²) - 1/x³

=> x³ - 3x + 3/x - 1/x³

=> x³ - 1/x³ - 3x + 3/x

Answer 2

Answer:

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Step-by-step explanation:

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