x+1/x=3 ,
find x^2 +1/x^2 ,
x^4+1/x^4
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If x+1/x=3
Square on both sides,
(x+1/x) ²=3²
x²+1/x²+2*x*1/x=9
x²+1/x²=9-2
x²+1/x²=7
Then again, square on both sides,
(x²+1/x²)²=7²
x⁴+1/x⁴+2*x²1/x²=49
x⁴+1/x⁴+2=49
x⁴+1/x⁴=49-2
x⁴+1/x⁴=47
I hope this much will help you
Square on both sides,
(x+1/x) ²=3²
x²+1/x²+2*x*1/x=9
x²+1/x²=9-2
x²+1/x²=7
Then again, square on both sides,
(x²+1/x²)²=7²
x⁴+1/x⁴+2*x²1/x²=49
x⁴+1/x⁴+2=49
x⁴+1/x⁴=49-2
x⁴+1/x⁴=47
I hope this much will help you
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