Math, asked by iittssmmee88, 11 months ago

(x-1) (x-3)>0
Solve it by wavy curvy method​

Answers

Answered by gangobangupbjhf8
3
Answer:

Please see the explanation.

Explanation:

Look at #(x + 1)(x - 3) = 0

This means that the function is 0 at x=−1andx=3.

Also, it means that the sign of the corresponding factor changes sign at that value of x.

At values of x < -1:

Both (x+1) and (x−3) are negative. A negative multiplied by a negative is a positive, therefore, x < -1 is one of the regions where (x+1)(x−3)>0. Let's make a note of that:

x<−1

At values between -1 and 3:

(x+1) is positive but (x−3) is still negative. A positive multiplied by a negative is negative, therefore, this is NOT a region for (x+1)(x−3)>0

At values x>3:

Both (x+1) and (x−3) are positive. A positive multiplied by a positive is a positive, therefore, x > 3 is one of the regions where #(x + 1)(x - 3) > 0. Let's make a note of that:

x<−1andx>3

We have no more regions to investigate, therefore, the above is our answer.

MARK AS BRIANLIEST

iittssmmee88: Thanks a lott
divyansh00722: Mark me as branliest
gangobangupbjhf8: rlly
divyansh00722: ???
divyansh00722: 101010101 101010101 1st
gangobangupbjhf8: ty
Similar questions