x +1/x=3 then find x⁵+1/x⁵=? Please give full explanation.
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Step-by-step explanation:
Given:-
x +1/x=3
To find:-
find x⁵+1/x⁵
Solution:-
Given that
x + 1/x =3 -----------(1)
on squaring both sides then
(x + 1/x )^2=3^2
=>x^2 + 2(x)(1/x) + (1/x)^2 =9
(since (a+b)^2=a^2+2ab+b^2)
=>x^2 + 2 + (1/x)^2 =9
=>x^2 + (1/x)^2 = 9-2
x^2 + (1/x)^2 = 7 -------(2)
On cubing both side of the equation (1) then
(x + 1/x)^3=3^3
(since (a+b)^3 = a^3+ b^3 +3ab(a+b))
=>x^3 +1/x^3+ 3(x)(1/x)(x+1/x)=27
=>x^3+1/x^3+3(3)=27 (from(1))
=>x^3+1/x^3+9=27
=>x^3+1/x^3=27-9
=>x^3+1/x^3=18-------(3)
Now multiplying (2)&(3)
(x^2+ 1/x^2)(x^3+1/x^3)=7×18
=>(x^2×x^3)+(x^2/x^3)+(x^3/x^2)+(1/x^2×1/x^3)=126
=>x^5+ 1/x +x + 1/x^5=126
=>x^5 + 1/x^5 + 3=126
=>x^5+1/x^5=126-3
x^5+1/x^5=123
Answer:-
The value of x^5+1/x^5=123
Used formulae:-
- (a+b)^2=a^2+2ab+b^2
- (a+b)^3=a^3+b^3+3ab(a+b)
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