(x - 1) (x – 3); x = 1, x = 3
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From question x+1/x = √3
x+1/x = √3
Cubing on both LHS and RHS we get,
(x+1/x)³ =(√3)³
X³ + (1/x³) + 3(x+ (1/x)) = 3√/3
x³ +1/x³ + 3(√3)= 3√3
By transporting we get
x³ +1/x³ + 3√3-3√/3=0
x³ + 1/x³ = 0
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