Question

(x-1/x +3)(x+1/x+3) solve using suitable identity ​

Answer 1

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$(x - 1 \div x + 3)(x + 1 \div x + 3) \\ \\ {(x - 1)}^{2} \div {(x + 3)}^{2} \\ \\ ({x}^{2} + 1 - 2x) \div ({x}^{2} + 9 + 6x)$

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Answer 2

Answer:

(x-1/x+3) (x+1/x+3)=0

(x-1) (x+1)/x^2+6x+9=0

x^2-(1^2)/x^2+6x+9=0

x^2-1=x^2-6x+9

-1= -6x+9

6x=9+1

x=10/6

x=5/3