Math, asked by NABANKUR10, 1 year ago

(x‐1)(x+3)(x-2)(x-6)+96 ....FACTORIZE​

Answers

Answered by adikandamahakud275
10

Answer:

(x -1) (X+3) (x-2) (x-6)+96=0

(x²+3x-x-3) (x²-6x-2x+12) +96=0

(x²+2x-3) (x²-8x+12 )+96=0

x⁴-8x³+12x²+2x³-16x²+24x-3x²+24x-36=0

then by slove you can find the answer

mark as brainlist answer

THANK YOU

Answered by as1965286p7d7zu
1

Answer:

We have ,

             >> (x‐1)(x+3)(x-2)(x-6)+96

Step-by-step explanation:

hence,

        >>   {x²-2x-3}{x²-8x+16}+96

        >>   {x^4-6x³-7x²+48x+60}

   

I HOPE IT HELPS.

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