(x+1)(x-3)(x-4) find products
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(x+1)(x-3)(x-4)
= (x+1)[x(x-4)-3(x-4)]
= (x+1)(x²-4x-3x+12)
= (x+1)(x²-7x+12)
= x(x²-7x+12)+1(x²-7x+12)
= x³-7x²+12x+x²-7x+12
= 2x²-6x²+5x+12
Therefore.,
(x+1)(x-3)(x-4) = 2x²-6x²+5x+12
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Answered by
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Answer:
x³-6x²-11x+12
Step-by-step explanation:
Multiplying first two brackets
(x²-3x+x-3)(x-4)
(x²-2x-3)(x-4)
(x³-4x²-2x²+8x-3x+12)
x³-6x²+5x+12
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