Question

(x+1)(x+3)(x-4)(x-6)+24​

Answer 1

Answer:

(x+1) (x-4) (x+3) (x-6) + 24 = 0

(x2 - 3x -4) (x2 -3x -18) +24 = 0

Now let x2 - 3x = t (where x2 is x-squared)

So the equation becomes:

(t-4)(t-18) + 24 = 0

t2 -22t + 72+24 = 0

t2-22t + 96 = 0

t2 - 16t -6t +95 = 0

(t-16) (t-6) = 0

t = 16,6

x2 - 3x = {16,6}

Answer 2

Answer:

I hope this will help you

Step-by-step explanation:

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