(X+1)(X+3)(x-4)(x-6)+24 factorise
Answers
(x+1) (x-4) (x+3) (x-6) + 24 = 0
(x2 - 3x -4) (x2 -3x -18) +24 = 0
Now let x2 - 3x = t (where x2 is x-squared)
So the equation becomes:
(t-4)(t-18) + 24 = 0
t2 -22t + 72+24 = 0
t2-22t + 96 = 0
t2 - 16t -6t +95 = 0
(t-16) (t-6) = 0
t = 16,6
x2 - 3x = {16,6}
now its quadratic equation, help yourself :)
mark brainlist and follow me
sᴏʟᴜᴛɪᴏɴ ⤵️
(x+1)(x+3)(x-4)(x-6)+24
=(x+1)(x-4)(x+3)(x-6)+24
=(x²-3x-4)(x²-3x-18)+24
=(a-4)(a-18)+24[let a=x²-3x)
=a²-4a-18a+72+24
=a²-22a+96
=a²-16a-6a+96
=a(a-16)-6(a-16)
=(a-16)(a-6)
=(x²-3x-16)(x²-3x-6) [ putting the value of a]
ᴍɪᴅᴅʟᴇ ᴛᴇʀᴍ ғᴀᴄᴛᴏʀɪᴢᴀᴛɪᴏɴ
Factorising is the reverse of expanding brackets, so it is, for example, putting 2x² + x - 3 into the form (2x + 3)(x - 1). This is an important way of solving quadratic equations. The first step of factorising an expression is to 'take out' any common factors which the terms have.
In Quadratic Factorization using Splitting of Middle Term which is x term is the sum of two factors and product equal to last term. To Factor the form :ax 2 + bx + c. Factor : 6x 2 + 19x + 10. 1) Find the product of 1st and last term( a x c).