(x+1/x-4)^2 = (x+8/x-2)
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[(x+1)²/(x+4)²] = x+8/x-2
(x²+1+2x/x²+16+8x)=x+8/x-2
1+2x/16+8x= x+8/x-2
(1+2x)(x-2)= (16+8x)(x+8)
x-2+2x²-4= 16x+128+8x²+64
2x²+x-6= 8x²+16x+192
8x²+16x+192-2x²-x+6=0
6x²+15x+198=0
3(2x²+5x+66)=0
2x²+5x+66=0
2x²+11x-6x+66=0
x(2x+11)-6(x+11)=0
(x+11)(x-6)=0
x=6
x=-11
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Answer is 128/45
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