x - (1/x) = 4 then x + (1/x) will be
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given,
x-(1/x) = 4, find x+(1/x)
if we use, (a-b)² = a² -2ab + b² formula,
(x-(1/x)) = x² - 2(x)(1/x) + (1/x)²
substituting x-(1/x) for 4,
4² = x² - 2 + 1/x² (since x is being multiplied with 1/x and -2, we can cancel out both the x, and we get -2)
16 = x² + 1/x² - 2
16+2 = x² + 1/x²
18 = x² + 1/x²
now that we know, x² + 1/x² = 18, let us use the identity
(a+b)² = a² + 2ab + b²
(x+1/x)² = x² + 2(x)(1/x) + 1/x²
(again here x and 1/x gets cancelled)
(x+1/x)² = x² +1/x² + 2 (since it's addition we can rearrange the terms)
(x+1/x)² = 18+2 (as we before we found out x²+1/x² = 18)
(x+1/x)² = 20
(x+1/x) = √20
hope it helps
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