Question

(x-1) (x-4) +(x-3) (x-2) =10÷3​

Answer 1

Step-by-step explanation:

x-1/x-2 + x-3/x-4 = 10/3

(x^2- 5x +4 +x^2 -5x+ 6)/(x-2) (x-4)= 10/3

(2x^2- 10x +10)/(x^2-6x+8)= 10/3

2(x^2- 5x +5)/(x^2-6x+8) = 10/3

Dividing both sides by 2 ,we get

(x^2- 5x +5)/(x^2-6x+8) = 5/3

By applying component and dividendo

(x^2- 5x +5+x^2-6x+8)/ (x^2- 5x +5-x^2+6x-8)=5+3/5-3

(2x^2-11x+13)/(x-3)=8/4

2x^2-11x+13=4(x-3)

2x^2-11x+13=4x-12

2x^2 -15x+25=0

2x^2 - 10x -5x +25 =0

2x(x-5)-5(x-5)=0

So, x=5/2, 5

Reject 5/2 and we get

x =5

Answer 2

Step-by-step explanation:

x^2 -4x-x+4+x^2-3x-2x+6=10÷3

x^2-5x+4+6+x^2-5x=10/3

2x^2-10x+10=10/3

6x^2-30x+30=10

6x^2-30x+20=0

3x^2-15x+10=0. divide by 2

now solve this after that