Question

X+1/x=41/20 solve the following equation by factorization

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$x+\frac{1}{x}=\frac{41}{20} \\\\\frac{x^2+1}{x} =\frac{41}{20}\\ \\20x^2+20=41x\\\\20x^2-41x+20=0\\\\ 20x^2 - 25x - 16x + 20=0\\\\5x(4x-5)-4(4x-5)=0\\\\(5x-4)(4x-5)=0\\\\x=\frac{4}{5} \\\\or\\\\x=\frac{5}{4}$