x-1/x=6,find x+1/x
please help
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Answer:
As we know (a-b)=[(a+b)^2-4ab]^1/2
It is given that x+1/x=6
So assume that a=x and b=1/x
Substitute in the formula
We get (x-1/x)=[(6)^2-4(x.1/x)]^1/2
(x-1/x)=[36-4]^1/2=(32)^1/2
=4(2)^1/2
(OR)
= (32)^1/2
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