(x-1)(x-6) is greater than 0
what are the values of x?
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Answer:
x ∈ (-∞ , 1) U (6 , ∞).
Step-by-step explanation:
(x-1)(x-6) > 0
Consider x<1 ⇒ x-1<0
If x < 1 it is definitely less than 6( 1 < 6),
i.e x < 6 ⇒ x - 6 <0.
Hence both terms are negative.
Multiplying two negative terms gives always positive result i.e greater than zero.
Now consider 1 < x < 6,
x-1 > 0 and x-6 < 0.
One term is positive and one term is negative. So multiplying them gives us a value less than zero(negative).
Consider x >6
If x >6 it is definitely greater than 1, i.e x >1
Hence, x-1 >0 and x-6 >0.
Multiplying two positive numbers gives always a positive value i.e greater than zero.
From above discussion it is clear that x must be either less than 1 or greater than 6 for (x-1)(x-6)<0,
i.e x ∈ (-∞ , 1) U (6 , ∞).
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