Math, asked by pratham0904, 6 months ago

(x - 1)(x + 6) - (x - 2)(x - 3) = 3​

Answers

Answered by basumatarybabull
1

Answer:

The answer is 1/9

Step-by-step explanation:

(x-1) (x+6)- (x-2) (x-3)=3

x²+6x-x-6 -x²+3x-2x+6=3

6x-x+3x-2x-6+6=3

5x+3x+x=3(and -6+6 is cancelled)

9x=3

x=3/9

x=1/9

Hope it will help you

Answered by Anonymous
25

Question :-

Find the value of x in the given equation - \rm (x-1)(x+6) - (x-2)(x-3) = 3

Answer :-

\rm (x-1)(x+6) - (x-2)(x-3) = 3

\rm x(x+6)-1(x+6) - [x(x-3) -2(x-3)] = 3

\rm x^2 + 6x - x - 6 - [ x^2 - 3x - 2x + 6 ] = 3

\rm x^2 + 6x - x - 6 - x^2 + 3x + 2x - 6 = 3

\rm \cancel {x^2} - \cancel {x^2} + 6x - x + 3x + 2x - 6 - 6 = 3

\rm 10x - 12 = 3

\rm 10x = 12 + 3

\rm 10x = 15

\rm x = \dfrac{15}{10}

\rm x = \dfrac{3}{2}

\boxed{\rm x = 1.5}

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