Question

(x-1) (x+6)- (x-2)(x-3)=3​

Answer 1

Answer...

$\sf(x - 1)(x + 6) - (x - 2)(x - 3) = 3 \\ \sf = x(x + 6) - 1(x + 6) - x(x - 3) - 2(x - 3) = 3 \\ \sf = {x}^{2} + 6x - x - 6 - {x}^{2} + 3x - 2x + 6 = 3 \\ \sf= {x}^{2} - {x}^{2} + 6x + 3x - 2x - x - 6 + 6 = 3 \\ \sf = 9x - 3x = 3 \\ \sf = 6x = 3 \\ \sf = x = \frac{3}{6} \\ \sf{x = \frac{ \cancel{3}}{ \cancel{6}} } = 2 \\ \sf =x = 2$