Question

(x-1)(x+6)-(x-2)(x-3)=3




ans in paper​

Answer 1

$\left(x-1\right)\left(x+6\right)-\left(x-2\right)\left(x-3\right)=3$

$=x^2+5x-6-\left(x-2\right)\left(x-3\right)=3$

$=x^2+5x-6-x^2+5x-6=3$

$=10x-12=3$

$=10x-12+12=3+12$

$=10x=15$

$x=\dfrac{3}{2}$

Answer 2

Answer:

answer for the given problem is given