Question

[ (x+1/x) ] -6(x6+1x6)-2]/ [ (x+1/6)3+x3+1/x3] = (x+1)2=x2 x2+1+2x= x2 2x+1=0 x= -1/2 a2= 1/2= -1/2 = (1/4=1/4) −6( x6+1 )- 2= 1/4 x6 6x12−2x6−6x6=14 x6 −6x12−2x6−6=1/4x6 x+1/6)3+x3+1/x3 = (x+1/6)(3)+x3+1 x3 x6+3x4+1/2x3+1 x3 =2x6+6x4+x3+2 2xxx =2x6+6x4+x3+2 2x3

Answer 1

Answer:

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