x+1/x=7 then x^3+1/x^3 please help me tomorrow I has exam
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x+(1/x)=7
cubing on both sides,
[x+(1/x)]^3=7^3
x^3+(1/x)^3+(3×x×1/x)×( x+(1/x))= 316
x^3+(1/x)^3+3 (x+1/x)= 316
x^3+(1/x)^3= 316-3×(x+1/x)
we know that (x+1/x)=7,
so x^3+(1/x)^3= 316-3×7
x^3+(1/x)^3= 316-21
x^3+(1/x)^3= 295
HOPE IT HELPS...
All the very best for your exams...
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