(x^ + 1) (x^-9)/(x^+2x+1) <= 0..find the value of x internal of x satisfying.
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Step-by-step explanation:
is
A
x∈(−∞,−
3
]∪[1,∞)
As, [x]−1+x
2
≥0;
⇒ x
2
−1≥−[x]
Thus, to find the points for which f(x)=x
2
−1 is greater than or equal to g(x)=−[x],
where the two functions f(x) and g(x) can be plotted as shown in the graph.
Thus, from the graph f(x)≥g(x) when x∈(−∞,A]∪[B,∞) where A is point of intersection of x
2
−1 and −[x]=+2
∴x
2
−1=+2 ie, x=−
3
=A and B=1
∴[x]−1+x
2
≥0 is satisfied, ∀x∈(−∞,−
3
]∪[1,∞)
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