(x+1/x)=9and(x^2+1/x^2)=53,find the value of x-1/x
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Answer is Sq. Rt of 51,
Here is how, As we know,
(a−b)2=a2+b2−2∗a∗b(a−b)2=a2+b2−2∗a∗b
Therefore,
(x−1/x)2=x2+(1/x)2−2∗x∗(1/x)(x−1/x)2=x2+(1/x)2−2∗x∗(1/x)
=53−2=53−2
=51=51
therefore, x - 1/x = Sq. Rt of 51
Hope it helps!!
Mark as Brainliest! :)
Here is how, As we know,
(a−b)2=a2+b2−2∗a∗b(a−b)2=a2+b2−2∗a∗b
Therefore,
(x−1/x)2=x2+(1/x)2−2∗x∗(1/x)(x−1/x)2=x2+(1/x)2−2∗x∗(1/x)
=53−2=53−2
=51=51
therefore, x - 1/x = Sq. Rt of 51
Hope it helps!!
Mark as Brainliest! :)
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