∣x+1∣+∣x∣>3
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Answered by
1
Step-by-step explanation:
∣x−1∣≥∣x−3∣
⇒∣x−1∣−∣x−3∣≥0
∣x−1∣−∣x−3∣=⎩⎪⎪⎪⎨⎪⎪⎪⎧−22x−42ifififx<11≤x≤3x>3
if x<1
⇒−2≥0 not possible
if 1≤x≤3
⇒2x−4≤0⇒x≤2⇒x∈[2,∞)
∵1≤x≤3
⇒x∈[2,3]
if x>3
⇒2≤0 is true then
x∈(3,∞)
then x∈[2,3]∪(3,∞)
x∈[2,∞)
hope it helps uh!
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Answered by
0
Step-by-step explanation:
write again this question ,I'm not understood
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