Question

x+1/x=root 3 , find x^19+1/x^19

Answer 1

this condition is not possible since sum of two numbers which are reciprocals of each other is at least 2, while √3 is 1.732...

Answer 2

Answer:

Given :

• x + 1/x = root 3

note that :

• x+ 1/x = 2 cos ( pie /6)

= [ cos ( pie /6 ) + I sin ( pie /6 ) ] +

[ cos (- pie /6 ) + I sin ( - pie /6 ) ]

so by de moivre's formula

x ^17 +1 / x^ 17 = 2 cos ( 17 pie /6 )

• = 2 cos ( 5pie / 6)
• = -√3

plz mark it as a brainlist