X+1/x=root3, evaluate :x³+(1/x³)
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X+1/x=root3, evaluate :x³+(1/x³) is [x3+ y3 + 3xy( x+ y) ] = x3 + 1/x3 + 3x1/x ( x+ 1/ x) = √3^3 = x+1/x = √3
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