Question

(x+1/x) whole cube
pleas fi

Answer 1

By using the identity,
$( {x + y)}^{3} = {x}^{3} + {y}^{3 } + 3 \times x \times y(x + y)$

${(x + \frac{1}{x} )}^{3} = {x}^{3} + { \frac{1}{x} }^{3} + 3 \times x \times \frac{1}{x} (x + \frac{1}{x} )$
$= {x}^{3} + \frac{1}{ {x}^{3} } + 3(x + \frac{1}{x} )$
$= {x}^{3} + \frac{1}{ {x}^{3} } + 3x + \frac{3}{x}$