(x - 1/x), (x + 1/x), (x ^ 2 + 1/(x ^ 2) , (x ^ 4 + 1/(x ^ 4)
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Step-by-step explanation:
dx
d
{
1+x+x
2
1+x
2
+x
4
}=ax+b
dx
d
{
1+x+x
2
1+2x
2
+x
4
−x
2
}=ax+b
⇒
dx
d
{
1+x+x
2
(1+x
2
)
2
−x
2
}=ax+b
⇒
dx
d
{
1+x+x
2
(1+x
2
+x)(1+x
2
−x)
}=ax+b
⇒
dx
d
(1+x
2
−x)=ax+b
⇒2x−1=ax+b
⇒a=2,b=−1
∴(a,b)=(2,−1)
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