Question

(X+1/X) (X-1/X) (X²+1/X²) (X⁴+1/X⁴)​

Answer 1

Answer:

$hey \: friend$

Using the identity (a+b)(a-b) =a²- b² in all cases

[x+1/x][x-1/x][x²+1/x²][x⁴+1/x⁴]

= [x²- 1/x²][x²+1/x²][x⁴+1/x⁴]

=[(x²)²- (1/x²)²][x⁴+1/x⁴]

=[x⁴- 1/x⁴][x+1/x⁴]

=(x⁴)² - (1/x⁴)²

=x⁸-1/x⁸

Answer 2

[x+1/x][x-1/x][x²+1/x²][x⁴+1/x⁴]

= [x²- 1/x²][x²+1/x²][x⁴+1/x⁴]

=[(x²)²- (1/x²)²][x⁴+1/x⁴]

=[x⁴- 1/x⁴][x+1/x⁴]

=(x⁴)² - (1/x⁴)²

=x⁸-1/x⁸