(x+1/x) (x-1/x) (x² +1/x²) (x⁴+1/x⁴)
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7
Step-by-step explanation:
Formula:
Using the identity (a+b)(a-b) =a²- b² in all
cases
[x+1/x][x-1/x][x²+1/x²][x^+1/x^]
= [x²- 1/x²][x²+1/x²][xª+1/x^]
=[(x²)²-(1/x²)²][x++1/x^]
=[x^- 1/x^][x+1/x^]
=(x4)²-(1/x4)²
=x³-1/x³
8
8
Required answer 08
Answered by
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Step-by-step explanation:
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