Math, asked by saketpaswan21, 2 days ago

(x+1/x) (x-1/x) (x² +1/x²) (x⁴+1/x⁴)​

Answers

Answered by Anonymous
7

Step-by-step explanation:

Formula:

Using the identity (a+b)(a-b) =a²- b² in all

cases

[x+1/x][x-1/x][x²+1/x²][x^+1/x^]

= [x²- 1/x²][x²+1/x²][xª+1/x^]

=[(x²)²-(1/x²)²][x++1/x^]

=[x^- 1/x^][x+1/x^]

=(x4)²-(1/x4)²

=x³-1/x³

8

8

Required answer 08

 \:

Answered by satbirsing9742987620
7

Step-by-step explanation:

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