Math, asked by shhxdjaln, 8 months ago

[x +1/x] [x^2 -1+1/x^2]...

please solve and send the solution...solve and tell..

please

will mark your answer as brainliest​..​

Answers

Answered by ritikahirve
1

Step-by-step explanation:

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Solution for X^2+x-192=0 equation:

Simplifying X2 + x + -192 = 0 Reorder the terms: -192 + X2 + x = 0 Solving -192 + X2 + x = 0 Solving for variable 'X'. Move all terms containing X to the left, all other terms to the right. Add '192' to each side of the equation. -192 + X2 + 192 + x = 0 + 192 Reorder the terms: -192 + 192 + X2 + x = 0 + 192 Combine like terms: -192 + 192 = 0 0 + X2 + x = 0 + 192 X2 + x = 0 + 192 Combine like terms: 0 + 192 = 192 X2 + x = 192 Add '-1x' to each side of the equation. X2 + x + -1x = 192 + -1x Combine like terms: x + -1x = 0 X2 + 0 = 192 + -1x X2 = 192 + -1x Simplifying X2 = 192 + -1x Reorder the terms: -192 + X2 + x = 192 + -1x + -192 + x Reorder the terms: -192 + X2 + x = 192 + -192 + -1x + x Combine like terms: 192 + -192 = 0 -192 + X2 + x = 0 + -1x + x -192 + X2 + x = -1x + x Combine like terms: -1x + x = 0 -192 + X2 + x = 0 The solution to this equation could not be determined.

Answered by Anonymous
3

Answer:

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