Question

(x+1)(x²-2) = (x+3)³
plz solve it​

Answer 1

Answer:

Given that (x^2–2x)^3 = 3^3,

then using the cube root of both sides of the equation and get

x^2 - 2x = 3 [cubic root in both side]

x^2 - 2x -3 = 0

x^2 - 3x + x -3 = 0 [middle term break]

(x-3)(x+1) = 0

Now, x-3 = 0 or x+1 = 0

so, x = 3 or -1.

Proof:

(x^2–2x)^3, with x=3 becomes (9–6)^3 = 3^3 = RHS, Correct.

(x^2–2x)^3, with x=-1 becomes (1+2)^3 = (3)^3 = RHS, Correct

Step-by-step explanation:

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Answer 2

Answer:

this is the correct answer

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