Question

x(1 - x2) dy + (2x2y - y -ax) dx = 0.
$x(1 - x^{2} } dy +( 2x^{2} - y - ax }^{3} )dx = 0$
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Answer 1

Step-by-step explanation:

x(1-x²)dy+(4y-y-ax)dx = 0

dxy-dx³y+3dxy-dax²= 0

dx(y-x²y+3y-ax)= 0

y-x²y+3y-ax=0

y(1+3)- x(x-a) = 0