Question

x=-1 ; y=2 2xy(1-3xy+7x²y²)​

Answer 1

$x = - 1 \: \: \: y = 2\\ \\ 2xy(1 - 3xy + 7 {x}^{2} {y}^{2} ) \\ \\ = 2 \times ( - 1)2(1 - 3( - 1)2 + 7 \times { (- 1)}^{2} \times {2}^{2} ) \\ \\ = - 4(1 + 6 + 28) \\ \\ = - 4(35) \\ \\ = - 140$

Answer 2

Answer:

-140

Step-by-step explanation:

2xy(1-3xy+7x²y²) = 2(-1)(2)[1-3(-1)(2)+7(-1²)(2²)]

= -4[1+6+28]

= -4×35

=-140

HOPE IT WILL HELP YOU