X=1,y=2 is solution of the equation a2x+ay=3,then find the value of a
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X=1
Y=2
2*1*a + a*2 = 3
2a + 2a = 3
4a = 3
a = 3/4
Y=2
2*1*a + a*2 = 3
2a + 2a = 3
4a = 3
a = 3/4
ziyakapoor69:
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Answered by
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Answer:
x=1 & y=2
substituting these values in a2x+ay=3
a2(1)+a(2)=3
a2+2a-3=0
solving the above quadratic equation...
-b±√b
we get 2 roots..
root 1: 2/3
root 2: -2
Step-by-step explanation:
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