X/1=y/2=z/3,prove that√4x+5y+3z=5x
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Answered by
1
Answer:
solved
Step-by-step explanation:
X/1=y/2=z/3
z = 3x , y = 2x , x = x
√4x+5y+3z=√4x+10x+9x=√(23x)
Answered by
1
Answer:
similar answer, try it my own
Step-by-step explanation:
3
+b
3
+c
3
=(a+b+c)(a
2
+b
2
+c
2
−ab−bc−ca)+3abc
If a+b+c=0, then a
3
+b
3
+c
3
=3abc
Now, given (x−2y)
3
+(2y−3z)
3
+(3z−x)
3
Here, a=(x−2y), b=(2y−3z), c=(3z−x) and a+b+c=(x−2y)+(2y−3z)+(3z−x)=0
Therefore
(x−2y)
3
+(2y−3z)
3
+(3z−x)
3
=3(x−2y)(2y−3z)(3z−x)
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