Question

X=1,y=2and z=3 what is the value of x power1+y power2+2xyz

Answer 1

$\huge {\red {\mathfrak {Question :-}}}$

• X=1, y=2 and z=3 , what is the value of $\sf {x+y^2+2xyz}$?

$\huge {\pink {\mathfrak {Solution :-}}}$

$\underline{\bold {Given:}}$

• x= 1
• y=2
• z=3

$\underline{\bold {To\:Find:}}$

• The value of $\sf {x+y^2+2xyz}$.

Now by putting value we get :

$\longrightarrow x + {y}^{2} + 2xyz \\ \\ \longrightarrow 1 + {(2)}^{2} + 2 \times 1 \times 2 \times 3 \\ \\ \longrightarrow 1 + (2\times 2) + 12\\ \\\longrightarrow 1+4+12 \\ \\ \longrightarrow 17$

$\green {\tt{\therefore{The\:value\:of\:x + {y}^{2} + 2xyz \:is\:17.}}}$

Answer 2

Solution:

Given,

• x=1
• y=2
• z=3

To find,

• The value of x+y^2+2xyz

Now, by putting values we get:

-->x+y^2+2xyz

-->1+(2)^2+2×1×2×3

--> 1+(2×2) +12

--> 1+4+12

--> 17.

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