Question

X=1, Y=4, Z=2, x^3+Y^2+Z^2-2XYZ find xyz value​

Answer 1

Answer:

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Step-by-step explanation:

${x}^{3} + {y}^{2} + {z}^{2} - 2xyz \\ \\ (1) {}^{3} + {(4)}^{2} + (2) {}^{2} - 2(1)(4)(2) \\ \\ 1 + 16 + 4 - 16 \\ \\ 21 - 16 \\ \\ 5$