Math, asked by Soumya3456, 1 year ago

X(√10+√20)(√5-√4)=10


MauryaAJ: hii

Answers

Answered by MauryaAJ
0

x( \sqrt{10 }  \times  \sqrt{5 }  +  \sqrt{20 }  \times  \sqrt{5}  +  \sqrt{10}  \times   -  \sqrt{4}   +  \sqrt{20}  \times   -  \sqrt{4})   = 10 \\ x( \sqrt{50}  +  \sqrt{100}   -  \sqrt{40}  -  \sqrt{80} ) = 10 \\ x( \sqrt{150}  -  \sqrt{120})  = 10 \\ x \sqrt{30}  = 10 \\ x = 10 \div  \sqrt{30}

I hope it me help you mark me as brainliest


mkrishnan: is it root 50 +root 100 =roo150
Answered by mkrishnan
0
Answer:

Step-by-step explanation:

GIVEN

X(√10+√20)(√5-√4)=10

X =10/[(√10+√20)(√5-√4)]
please see the attachment
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mkrishnan: i do it correctly please make me brainliest
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