Question

X + 10’ is 20% more than ‘Y – 8’. If X is 22 more than Y, then find the value of Y.​

Answer 1

Given :- 'X + 10' is 20% more than 'Y – 8’. If X is 22 more than Y, then find the value of Y. ?

Solution :-

given that,

→ (x + 10) = 20% more than (y - 8) .

So,

→ (x + 10) = 120 % of (y - 8)

→ (x + 10) = (120/100) * (y - 8)

→ (x + 10) = (6/5) * (y - 8)

→ 5(x + 10) = 6(y - 8)

→ 5x + 50 = 6y - 48

→ 6y - 5x = 50 + 48

→ 6y - 5x = 98 ------------ Eqn.(1)

Also, given that,

→ x - y = 22

So,

→ x = (22 + y)

Putting value of x in Eqn.(1) now,

→ 6y - 5(22 + y) = 98

→ 6y - 110 - 5y = 98

→ 6y - 5y = 98 + 110

→ y = 208 (Ans.)

Hence, value of y is 208.

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If (x+10)% of 240 is 60% more than x% of 180. then 15% of (x+20) is what percent less than 25% of x?

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