x^+10x+2=0
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Answer:
x²+10x+2=0
a=1; b=10; c=2
∴D= b²-4ac = 10²-4x1x2 = 100-8 = 92
Since D>0, ∴the equation has 2 equal roots
∴Roots= -b±√D/2a = -10±√92/2 = -10±4√23/2 = 2(-5±2√23)/2 = -5±2√23
Hence, roots are (-5+2√23) and (-5-2√23)
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