(x+11)/7 + 2y =10 and 3x = 8+(y+7)/11 by substitution method
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heya...!!!!!
(x + 11)/7 + 2y = 10
=> (x + 11 + 14y)/7 = 10
=> x + 14y = 70 - 11
=> x + 14y = 59
=> x = ( 59 - 14y)--------(1)
3x = 8 + (y + 7)/11
=> 3x = (88 + y +7)/11
=> 3x = (95 + y))/11
=> 33x = 95 + y
=> 33( 59 - 14y) = 95 + y--------from --(1)
=> 1947 - 462y = 95 + y
=> 1852 = 463y
=> y = 1852/463
=> y = 4 put in --(1)
we get
x = 59 - 4 × 14
=> x = 59 - 56
=> x = 3
(x + 11)/7 + 2y = 10
=> (x + 11 + 14y)/7 = 10
=> x + 14y = 70 - 11
=> x + 14y = 59
=> x = ( 59 - 14y)--------(1)
3x = 8 + (y + 7)/11
=> 3x = (88 + y +7)/11
=> 3x = (95 + y))/11
=> 33x = 95 + y
=> 33( 59 - 14y) = 95 + y--------from --(1)
=> 1947 - 462y = 95 + y
=> 1852 = 463y
=> y = 1852/463
=> y = 4 put in --(1)
we get
x = 59 - 4 × 14
=> x = 59 - 56
=> x = 3
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