x^12-1. factorize it
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x^12 - 1
=( x^6 )^2 - (1)^2
=( x^6 - 1 ) (x^6 + 1 )
={ (x^3 )^2 - (1)^2 } { (x^6 + 1 )
=( x^3 - 1 ) ( x^3 + 1 ) ( x^6 + 1 )
={ x^3 - ( 1 )^3 } (x^3 + 1 ) ( x^6 + 1 )
=( x - 1 ) (x^2 + x + 1 ) ( x^3 +1 ) ( x^6 + 1 )
【 hope I helpes 】
=( x^6 )^2 - (1)^2
=( x^6 - 1 ) (x^6 + 1 )
={ (x^3 )^2 - (1)^2 } { (x^6 + 1 )
=( x^3 - 1 ) ( x^3 + 1 ) ( x^6 + 1 )
={ x^3 - ( 1 )^3 } (x^3 + 1 ) ( x^6 + 1 )
=( x - 1 ) (x^2 + x + 1 ) ( x^3 +1 ) ( x^6 + 1 )
【 hope I helpes 】
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