Question

X, 13,y&3 are in AP, find the value of x and y

Answer 1

Step-by-step explanation:

here,

x,13,y,3 are in AP

now, AP between 13 and 3

here no of terms =3

first term 'a' = 13

let common difference be 'd'

a/q

term3=3

a+(3-1)d=3

a+2d=3

13+2d=3

2d=3-13

2d=-10

d=-10/2

d= -5

.'.common difference d= -5

now,

x+(-5)=13

x-5=13

x=13+5

x=18

and

13+(-5)=y

y=13-5

y=8

.'.x=18 and y=8