Question

(x-16)(x-19)=25/64 solve this sums please

Answer 1

Sorry due i am unable to find the right answer
I found that it will be
x^2-35x+304=25/64

Answer 2

The value of x is $\frac{153}{8} , \frac{127}{8}$

Step-by-step explanation:

Given : (x-16)(x-19)=25/64

To Find : Value of x

Solution:

$(x-16)(x-19)=\frac{25}{64}\\64(x-16)(x-19)=25\\64(x^2-19x-16x+304)=25\\64x^2-2240x+19456-25=0\\64x^2-2240x+19431=0$

(8x-153)(8x-127)=0

$x=\frac{153}{8} , \frac{127}{8}$

Hence The value of x is $\frac{153}{8} , \frac{127}{8}$

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