Question

√x+16 -√x =2 then X equals to-

Answer 1

Answer:

Step-by-step explanation:

$\sqrt{x} +16-\sqrt{x} =2\\\\\sqrt{x} +16=\sqrt{x} + 2\\\\\\\(\sqrt{x} +16)^{2} =(\sqrt{x} +2)^{2}\\\\ x+256+32\sqrt{x} =x+4+4\sqrt{x} \\\256+32\sqrt{x} =4+4\sqrt{x} \\\\32(8+\sqrt{x} )=4(1+\sqrt{x} )\\\\8(8+\sqrt{x} )=1+\sqrt{x} \\\\64+8\sqrt{x} = 1+\sqrt{x} \\\\7\sqrt{x} =-63\\\\(\sqrt{x} )^{2}=(-63/7)^{2}\\ \\ x=(-9)^{2}\\ x=81$