Question

x+1upon x=11 find the value of x square +1 upon x square​

Answer 1

hey mate

here is your answer

${(x + \frac{1}{x} )}^{2} = {x}^{2} + 2 + \frac{1}{ {x}^{2} } \\ 121 = {x}^{2} + 2 + \frac{1}{ {x}^{2} } \\ 119 = {x}^{2} + \frac{1}{ {x}^{2} }$

hope it helps u.... ☺☺